Tuesday, March 14, 2017

#41 Same Direction Cannon Double Headed Snake Pawn Formation vs Double Ranked Chariot - Black P3+1 then E3+1 follow by H2+3

 #41 Same Direction Cannon Double Headed Snake Pawn Formation vs Double Ranked Chariot - Black P3+1 then E3+1 follow by H2+3


Outcome: Advantage go to Red

  1. C2=5  C8=5    2. H2+3  H8+7
  3. R1=2  R9+1    4. P3+1  R9=4
  5. H8+7  P3+1

We had discussed Black R4+3 R4+4, R4+5 and R4+7, advantages all go to Red.

In this post, we will start to discuss Black P3+1.

As mentioned earlier, the most efficient move Black would be H2+3 for proper horse.

Now Black plays P3+1, is to prevent Red to develop left horse. In this case, what is the most efficient move for Red?


  6. R2+5  …………

Correct move!

Black pawn became the target for Red!

In general, there are 3 main variations for Black.
1) E3+1
2) H2+3
3) C5-1

In this post, we will discuss E3+1 variation.

  6. …………  E3+1    7. C8=9  …………

Red C8=9 is a good move. Red should not C8+4, Black could R4+2.

Now is Black's turn. There are 3 main variations.

1) C2+2
2) H2+3
3) R4+2

In this post we discuss H2+3

  7. …………  H2+3

Black develops his right horse.

Therefore, what is the most effective move for Red?



  8. C9+4  …………

Corrent move!

  8. …………  R1=2    9. C9=8  R2=3
 10. C8=3  E7+9   11. R2=4  …………

This is the correct move for Red. If Red played R9=8 to develop his chariot, then Black could C2+2, R2+1, Black R4+4. Black gains some advantages.

 11. …………  C2+2   12. R4+2




Current board situation:
1) Red chariot is capturing Black's cannon and horse.Red will gain material.

Outcome: Advantage goto Red

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